How to substr version numbers string with javascript?

Question

I have strings with version numbers like:

"1.4.2.57"
"8.4.3"
"3.12.0.25"

I only need the first 3 numbers, I was going to use substr, but if the numbers are > 9 the substr will fail.

How can I extract x.x.x from strings like (x.x - x.x.x - x.x.x.x) where x is = [0-99]

^(\d+)\D+(\d+)\D+(\d+) should do it, you'll have to translate that to javascript regex though. You'll have the first 3 digits with any delimiters in your first three capture groups, you can change \D+ to (?:\s|-|\.)+ if you want to specify .,-, and space as your only valid delimiters with none capturing groups. — NorthGuard
– NorthGuard, Commented Jun 20, 2011 at 21:04

Brad Christie · Accepted Answer · 2011-06-20 21:04:04Z

2

var t = [
    "1.4.2.57",
    "8.4.3",
    "3.12.0.25"
    ];
for (var v = 0; v < t.length; v++){
    var ver = t[v].split('.');
    alert(ver.slice(0,3).join('.'));
}

Split by ., then slice to get only first 3 digits (in this case elements, since they were split to an array), then rejoin with . again.

answered Jun 20, 2011 at 21:04

Brad Christie

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2 Comments

riviraz Over a year ago

Cool, it even works when the version is like "1.5", I though he slice would show an error but it doesn't.

Brad Christie Over a year ago

@riviraz: Correct, slice will silently grab as much as it can, leaving you with only the desired portions.

Connor Smith · Accepted Answer · 2011-06-20 21:05:25Z

0

var no_periods = string.replace('.', '');
var new_string = no_periods.substr(0,2);

will get rid of all the periods and then just get the first three numbers, is that what you wanted?

answered Jun 20, 2011 at 21:05

Connor Smith

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