String Interpolation using Dictionary of Unknown Keys and Number of Elements

Question

item_list = [x for x in notion_position_block.collection.get_rows()]
item_dict = {x.title: len(x.get_property('potential_hires')) for x in item_list}

Which gets me what I want: {'Full Stack Engineer': 3, 'Social Media Manager': 2, 'Backend Software Engineer': 1}

The dictionaries key/value + num of elements will never be the same

How can I get this into a string if keys + num of elements are consistently changing?

What I am ultimately trying to get is:

Full Stack Engineer 3 
Social Media Manager 2
Backend Software Engineer 1

Edit:

Is it possible to get the dictionary into a string with some version of

''.format()

Sarol · Accepted Answer · 2020-10-03 06:12:13Z

1

If what you really want is a string, not the dictionary, I'd skip right to:

for x in notion_position_block.collection.get_rows():
    print(x.title, len(x.get_property('potential_hires')))

If you do still want that dictionary, you can skip the list. You're creating a list, then looping over it to make the dictionary. It seems easier to just go right for the dictionary right away.

item_dict = {x.title: len(x.get_property('potential_hires')) for x in notion_position_block.collection.get_rows()}

for title, total in item_dict.items():
    print(title, total)

Edit for "Is it possible to get the dictionary into a string with some version of ''.format()": I'd use str.join for that:

', '.join(f'{title}: {total}' for title, total in item_dict.items())

answered Oct 3, 2020 at 6:12

Sarol

1414 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

bobdawg Over a year ago

Thanks! Sorry I did not put that in the initial post

avarice · Accepted Answer · 2020-10-03 05:59:44Z

0

Try this:

for x in item_dict.keys():
  print(x,item_dict[x])

answered Oct 3, 2020 at 5:59

avarice

15.6k3 gold badges19 silver badges38 bronze badges

Comments

Grzegorz Gabrychowicz · Accepted Answer · 2020-10-03 06:03:48Z

0

I'm not sure If I understand you right, but this is how you can change this dictionary representation to the string form and put in a list.

Then if you want to have exactly the same outcome as you provided, you just have to make a basic for loop to print out the elements from the list

item_dict = {'Full Stack Engineer': 3, 'Social Media Manager': 2, 'Backend Software Engineer': 1}

string_rep = [(keys, values) for keys, values in item_dict.items()]
print(string_rep)

answered Oct 3, 2020 at 6:03

Grzegorz Gabrychowicz

1011 gold badge2 silver badges15 bronze badges

Comments

Jens · Accepted Answer · 2020-10-03 06:06:23Z

0

You can use the items() method to iterate over the key/value pairs of your dictionary:

>>> for key, value in item_dict.items():
...     print(key, value)
... 
Full Stack Engineer 3
Social Media Manager 2
Backend Software Engineer 1

answered Oct 3, 2020 at 6:06

Jens

9,2789 gold badges65 silver badges84 bronze badges

Comments

Timur U · Accepted Answer · 2020-10-03 06:06:52Z

0

For the: ‘ Full Stack Engineer 3 ’ it means 3 - dictionary number or how many this words involve in item_list? If first:

for i in item_dict.keys(): print(i,item_dict[i])

answered Oct 3, 2020 at 6:06

Timur U

4452 silver badges16 bronze badges

Collectives™ on Stack Overflow

String Interpolation using Dictionary of Unknown Keys and Number of Elements

5 Answers 5

1 Comment

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

5 Answers 5

1 Comment

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related