How to replace string with an int in list in python?

Question

In the following list, I want to replace "Sun" with a 0 and "Rain" with a 1. How can I do that?

precipitation = ["Sun", "Rain", "Rain", "Sun", "Sun", "Sun", "Sun", "Sun", "Sun", "Sun", "Rain", "Rain", "Rain", "Rain"]

for i in precipitation:  
  if precipitation[i] == "Sun":
    precipitation[i] = 0
  else:
    precipitation[i] = 1

for i in precipitation gives you the actual items in the list, not their respective indices. The simplest fix to your code is for i in range(len(precipitation)):, which will have i take the value of the indices. Simpler solutions also exist, but this one most closely matches what you have now. — Frank Yellin
– Frank Yellin, Commented Oct 11, 2020 at 5:42
Shivam, can you show your new code, that gives you all 1s? And as @TomRon points out, there are simpler solutions. — Frank Yellin
– Frank Yellin, Commented Oct 11, 2020 at 5:54

Gabio · Accepted Answer · 2020-10-11 09:02:54Z

3

You can do it using list comprehension:

precipitation = [0 if x == 'Sun' else 1 for x in precipitation]

edited Oct 11, 2020 at 9:02

answered Oct 11, 2020 at 5:57

Gabio

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2 Comments

JenilDave Over a year ago

I guess questioner wants 0 for 'Sun'.

Gabio Over a year ago

@JenilDave Changed it. Thank you!

DYZ · Accepted Answer · 2020-10-11 06:08:12Z

1

An elaboration of @Gabip's answer, using the fact that the boolean values are numerically represented as 0 and 1:

[int(x=='Sun') for x in precipitation]

answered Oct 11, 2020 at 6:08

DYZ

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Comments

Robin Sage · Accepted Answer · 2020-10-11 05:59:42Z

0

Try this...

precipitation = ["Sun", "Rain", "Rain", "Sun", "Sun", "Sun", "Sun", "Sun", "Sun", "Sun", "Rain", "Rain", "Rain", "Rain"]

for i in range(len(precipitation)):  
  if precipitation[i] == "Sun":
    precipitation[i] = 0
  else:
    precipitation[i] = 1
         
print(precipitation)

answered Oct 11, 2020 at 5:59

Robin Sage

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Comments

JenilDave · Accepted Answer · 2020-10-11 06:29:13Z

0

Adding to answers already present, using map()

list(map(lambda x: 0 if x=='Sun' else 1,a))

You can try this to avoid loops and list comprehensions

answered Oct 11, 2020 at 6:29

JenilDave

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