Divide array into two arrays and set values to odd and even

Question

I can't get a result I wanted:

Even Array is: 2, 18, 38, -10, 0, 104
Odd Array is: 3, 13, -5, 11

Two arrays where one contains even numbers another odd.

Here is the code:

let arrayMain = [2, 3, 13, 18, -5, 38, -10, 11, 0, 104];
let oddArray = [];
let evenArray = [];

for (let i = 0; i < arrayMain.length; i++){
    if (i % 2 == 0) {
        evenArray.push(arrayMain[i]);
    }
    else {
        oddArray.push(arrayMain[i]);
    }
}

console.log("Odd Array is " + oddArray);
console.log("Even Array is " + evenArray);

It gives me:

Odd Array is 3,18,38,11,104
Even Array is 2,13,-5,-10,0

How can I fix this?

i is the counter i % 2 will divide divide the array into odd and even places, not odd and even values. You need to do arrayMain[i] % 2 — VLAZ
– VLAZ, Commented Oct 15, 2020 at 7:50
Please add a debugger; inside the code and verify each value and condition. — adiga
– adiga, Commented Oct 15, 2020 at 8:02

Nina Scholz · Accepted Answer · 2020-10-15 07:49:30Z

3

You need to check the value, not the index.

if (arrayMain[i] % 2 == 0) {
//  ^^^^^^^^^^ ^

answered Oct 15, 2020 at 7:49

Nina Scholz

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