TypeError: not all arguments converted during string formatting(numbers counting)

Question

Write a Python program to count the number of even and odd numbers from input.

count_even = 0
count_odd = 0
numbers = input()
for x in numbers:
  for i in x:
    if i % 2 == 0 :
      count_even += 1
    else:
      count_odd += 1
print(count_even)
print(count_odd)

ERROR: Traceback (most recent call last): File "main.py", line 6, in if i % 2 == 0 : TypeError: not all arguments converted during string formatting 

What is your input ? From what I understand, input() returns a string — NHL
– NHL, Commented Oct 20, 2020 at 12:30

C. Fennell · Accepted Answer · 2020-10-20 21:04:40Z

1

First, I'm not sure why you are iterating twice over one list. Second, if you're expecting a list delinated by spaces, you need to split it into it's elements and then you need to convert each item to an integer that you can then iterate over.

count_even = 0
count_odd = 0
numbers = input()
print(numbers)
for x in numbers.split():
    if int(x) % 2 == 0:
        count_even += 1
    else:
        count_odd += 1
print(count_even)
print(count_odd)

answered Oct 20, 2020 at 21:04

C. Fennell

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Comments

Nathan · Accepted Answer · 2020-10-20 12:36:27Z

-1

I see a couple issues with the code. The first thing is, I don't see x and i being created or declared. The second thing is, when you do numbers = input(), the variable type of numbers is a string. You might want to change it to numbers = int(input())

answered Oct 20, 2020 at 12:36

Nathan

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3 Comments

gabi2000 Over a year ago

File "main.py", line 1, in <module> numbers = int(input()) ValueError: invalid literal for int() with base 10: '1 2 3' 

NHL Over a year ago

if you have spaces in your input, you can use : num=numbers.split() for i in num : if int(i)%2==0 :...

FinleyGibson Over a year ago

x and i are declared in the for loop. The question may have been modified since you posted this answer but you should now remove or update this answer as there is no need to explicitly create x and i.

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