Passing an arbitrary number of parameters to a function in python

Question

I have a python function which takes as input an arbitrary number of parameters. I beleive this is implemented via *args (thanks @Anurag Wagh for pointing this out). I would like to be able to pass to it a list of values. Here is the specific code I have:

from sympy import solve_poly_system, symbols
x,y,z = symbols('x y z')
print(solve_poly_system([y**2 - x**3 + 1, y*x], x, y))

Instead of passing x and y to solve_poly_system, I want to be able to pass it a list L something like so:

print(solve_poly_system([y**2 - x**3 + 1, y*x], L))

where L = [x,y].

Is this possible? Please note, although I am interested in the specific case of the solve_poly_system function, I am more broadly interested in the passing a list to any function in python that takes an arbitrary number of inputs.

To put this another way, I want to know how to pass a list of values to a function which takes *args as input. In particular I am interested in the case where the length of the list is not known until run time and may change during run time.

I think you are looking for *args type function. geeksforgeeks.org/args-kwargs-python — Anurag Wagh
– Anurag Wagh, Commented Oct 21, 2020 at 5:12
Thanks. This is what I am talking about, however the post you link to doesn't answer my question. I will edit my question shortly to reflect this. — Mathew
– Mathew, Commented Oct 21, 2020 at 5:16

Aniket Tiratkar · Accepted Answer · 2020-10-21 08:13:27Z

1

From your question, it looks like you know how to use *args in function definition and you are looking for a way to pass all the elements of a list to that function regardless of the length of the list. If that's your question, then here's your answer:

def function(x, *args):
    print(x)
    print(args)

x = 10
l = [5, 6, 7, 8]
function(x, *l)

Output:

10
(5, 6, 7, 8)

answered Oct 21, 2020 at 8:13

Aniket Tiratkar

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