It is possible send a http request of a view in another view?

Question

I would want to send a http request in a view. The request URL has relation to another view. Something like this:

class View_A(APIView):
    def get(self, request):
       return Response({'foo':'bar'})


class View_B(APIView):
    def post(self, request):
        # Here I would want to send a request to View_A, something like this:
        request_view_A = View_A.as_view().get('URL_FROM_VIEW_A')
        # ...
        return Response({'foo2':'bar2'})

I have seen this question which has a different focus, however don't working for me because http method from View_A (get) is different to http method from View_B (post).

willeM_ Van Onsem · Accepted Answer · 2020-10-26 23:14:35Z

3

You can do that with:

class View_B(APIView):
    def post(self, request):
        httpresponse = View_A().get(request)
        # …
        return Response({'foo2':'bar2'})

We here do not really make a HTTP request, we simply make a method call and use request as parameter.

That being said, often this means you should "encapsulate" the logic. Normally one thus defines extra function(s) or class(es), normally not views, that implement common logic that is then used in both views.

answered Oct 26, 2020 at 23:14

willeM_ Van Onsem

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3 Comments

Carmoreno Over a year ago

Hi @Willem, thanks for your answer and excuse me for my delay. Today I test your solution but I get this error: The response content must be rendered before it can be accessed. So, I found this asnwer: stackoverflow.com/questions/7258912/… but I don't understan yet.

willeM_ Van Onsem Over a year ago

@CarMoreno: can you share the traceback? Note that httpresponse will be Response object, not the dictionary wrapped in it.

Carmoreno Over a year ago

Yeah @Willem, my fault. Your solution working for me.However I'm going to take your advice, I will program a solution with an auxiliar function. Thank you! +25

pplonski · Accepted Answer · 2020-10-27 10:25:49Z

2

The alternative to Willem Van Onsem answer can be using the python requests package. The example:

import requests 
#...
class View_B(APIView):
    def post(self, request):
        response = requests.get(your_url)
        # ...
        return Response({'foo2':'bar2'})

answered Oct 27, 2020 at 10:25

pplonski

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