Given an array like:
5-element Array{String,1}:
"Computer science"
"Artificial intelligence"
"Machine learning"
"Algorithm"
"Mathematics"
How does one filter it by multiple conditions in Julia? For example, I want to obtain all the values that are not "Computer science" or "Artificial intelligence", hence, I want to obtain:
3-element Array{String,1}:
"Machine learning"
"Algorithm"
"Mathematics"
Maybe something like this?
julia> x = ["Computer science", "Artificial intelligence", "Machine learning", "Algorithm", "Mathematics"]
5-element Array{String,1}:
"Computer science"
"Artificial intelligence"
"Machine learning"
"Algorithm"
"Mathematics"
# Note the double parentheses, in order to build the
# ("Computer science", "Artificial intelligence") tuple
#
# It would also be possible (but probably less efficient) to put
# those values in a vector
julia> filter(!in(("Computer science", "Artificial intelligence")), x)
3-element Array{String,1}:
"Machine learning"
"Algorithm"
"Mathematics"
Edit: as mentioned in comments, if the list of values to filter out is longer, it might be more efficient to build a Set instead of a Tuple:
julia> filter(!in(Set(("Computer science", "Artificial intelligence"))), x)
3-element Array{String,1}:
"Machine learning"
"Algorithm"
"Mathematics"
Set that has O(ln(n)) search time rather than O(n) in case of a tuple or vector. For short filtering lists the proposed approach will be indeed fastest.