Formatting a String with the character %

Question

I was trying to format the String "2%" using the following code String.format("s%2", 2) and I got java.util.UnknownFormatConversionException: Conversion = 'End of String'.

So with the above result commes the questing how can I add '%' as a member of the output on the String

The Javadoc should help here. If I remember correctly you need to escape % by doubling. Also the conversion needs to start with a % so try"%s%%". — Thomas
– Thomas, Commented Nov 10, 2020 at 8:30
Check this answer here: stackoverflow.com/a/77988364/9133569 — M.Ed
– M.Ed, Commented Feb 13, 2024 at 13:41

Rapt0r · Accepted Answer · 2020-11-10 08:43:41Z

2

You represent a literal % by doubling it up...put %%.

To print "2%", where the 2 comes from the integer passed in as an argument to the format() call, you want this:

String str = String.format("%d%%", 2);

System.out.println(str);

Result:

2%

edited Nov 10, 2020 at 8:43

answered Nov 10, 2020 at 8:37

Rapt0r

793 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Tobi · Accepted Answer · 2020-11-10 08:35:05Z

0

You need to escape unwanted %. Otherwise String will take it as arguments. To escape single percent sign you need to add another percent character behind it ie. %%.

answered Nov 10, 2020 at 8:35

Tobi

411 silver badge4 bronze badges

Collectives™ on Stack Overflow

Formatting a String with the character %

2 Answers 2

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related