Suppose I have a list li=['project1','project2','project3']
I want to add these values as key to dictionary and value of first key should be completed rest onhold
projects can be any and value of first project in list should be completed rest onhold output required:
dict={'project1':'completed','project2':'onhold','project3':'onhold'}
li=['project1','project2','project3']
for trav_cont in li:
dict[trav_cont]='completed'
You might use enumerate to know position in list, i.e.:
li=['project1','project2','project3']
dct = {i: 'completed' if inx==0 else 'onhold' for inx, i in enumerate(li)}
print(dct) # {'project1': 'completed', 'project2': 'onhold', 'project3': 'onhold'}
I used so-called dict-comprehension here, combined with ternary if, so value is 'completed' if its first element (has index 0 as python indices are 0-based) else 'onhold'
You can create a dictionary with predetermined keys and a default value:
my_dict = dict.fromkeys(li, 'onhold')
my_dict['project1'] = 'completed'
Gives:
{'project1': 'completed', 'project2': 'onhold', 'project3': 'onhold'}
my_dict[next(iter(my_dict))] = 'completed' to set value for first key. (It will work only on python 3.6+)for idx, key in enumerate(li):
if idx == 0:
dixt[key] = 'completed'
continue
dict[key] = 'onhold'
else, you don't need continue there.
zip():my_dict = dict(zip(li, ('completed',) + ('onhold',) * (len(li) - 1))). Do not usedictas name of variable, you're shadowing build-in function.