input =
6:/BENM/Gravity Exports/REM//INV: 3267/FEB20:65:ghgh
6:/BENM/Tabuler Trading/REM//IMP/2020-341
original_regex = 6:[A-Za-z0-9 \/\.\-:] - bt this is taking full string 6:/BENM/Gravity Exports/REM//INV: 3267/FEB20:65:ghgh
modified_regex_pattern = 6:[A-Za-z0-9 \/\.\-:]{1,}[\/-:]
In the first string i want output till 6:/BENM/Gravity Exports/REM//INV: 3267/FEB20 but its giving till :65: Can anyone suggest better way to write this. Example as below https://regex101.com/r/pAduvy/1
You could for example use a capturing group with an optional part at the end to match the :digits:a-z part.
(6:[A-Za-z0-9 \/.:-]+?)(?::\d+:[a-z]+)?$
( Capture group 1
6:[A-Za-z0-9 \/.:-]+? Match any of the listed in the character class as least as possible) Close group 1(?::\d+:[a-z]+)? optionally match the part at the end that you don't want to include$ End of stringNote Not sure if intended, but the last part of your pattern [\/-:] denotes a range from ASCII range 47 - 58.
Or a more precise pattern to get the match only
6:/\w+/\w+ \w+/[A-Z]+//[A-Z]+(?:: \d+)?/[A-Z]*\d+(?:-\d+)?
6:/\w+/\w+ Match 6 and 2 times / followed by 1+ word chars and a space\w+/[A-Z]+//[A-Z]+ Match 1+ word chars, / and uppercase chars, // and again uppercase chars(?:: \d+)? Optionally match a space and 1+ digits/[A-Z]*\d+ Match /, optional uppercase chars and 1+ digits(?:-\d+)? Optionally match - and 1+ digits
^6:.*?(?=:\d|$) regex101.com/r/wpikoU/1 Or if the tag is optional ^(?:^6:)?.*?(?=:\d|$) regex101.com/r/pitdfR/1 If the 6 should not be hardcoded, you can use \d+ instead to match 1+ digits.