can one python function argument depend on another argument?

Question

I would like to have something like the following function:

calc_map(img_in, img_height, img_width, mapping = np.zeros((image_height, image_width)))
[function body]

apparently it is not possible that the default argument of mapping is depending on other arguments in that function. Is there another way around that without using image_height and image_width as global?

I would imagine to put this in my function:

calc_map(img_in, img_height, img_width)
mapping = np.zeros((image_height, image_width))
[function body]

but I also need to put an already existing mapping into the function and not having overwritten it..

appreciate any help, regards, eli

Samwise · Accepted Answer · 2020-11-17 14:41:15Z

2

Make the default None in the function signature, and then replace it inside the body with whatever you want:

def calc_map(img_in, img_height, img_width, mapping = None)
    if mapping is None:
        mapping = np.zeros((image_height, image_width))

answered Nov 17, 2020 at 14:41

Samwise

72.1k3 gold badges36 silver badges52 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

avarice · Accepted Answer · 2020-11-17 14:43:42Z

0

Make default value to False and check:

def calc_map(img_in, img_height, img_width, mapping = False)
    if not mapping:
        mapping = np.zeros((image_height, image_width))

answered Nov 17, 2020 at 14:43

avarice

15.6k3 gold badges19 silver badges38 bronze badges

Collectives™ on Stack Overflow

can one python function argument depend on another argument?

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related