How do you skip few index in a for...of loop in Javascript?

Question

with the good old for loop I can do things like:

for (let i=0; i<bla.length; i+=2){
...
}

So for every count, I can skip the index by doing a +2.

I know for...of is the future but I can't quite figure how to skip the index?

for (const [i, element] of bla.entries()) {
...
}

I know for...of is the future Does not mean you have to give up what you already have; You can still do what you want using filter or indexing but at this point it will be like "Swatting flies with a sledgehammer" you can do it but why — Shubham Srivastava
– Shubham Srivastava, Commented Nov 26, 2020 at 4:24
True, not given up things in the past. Maybe I should rephrase better. I'm learning how to convert from the old for loop to the new for ... of loop. — Vennsoh
– Vennsoh, Commented Nov 26, 2020 at 4:30
Also it is a good practice to use for of loop when you need to iterate over all the elements; Keep things simple easy to maintain. — Shubham Srivastava
– Shubham Srivastava, Commented Nov 26, 2020 at 4:38

Ayudh · Accepted Answer · 2020-11-26 04:20:18Z

2

The answer of this depends on whether you would like to preserve the original index, if so, you may add an if statement within the for loop

for (const [i, element] of bla.entries()) {
   if (!(i % 2)) {
       // do something here
   }
}

if you don't care about preserving the original index then you may just add a filter before or after entries:

for (const [i, element] of bla.entries().filter((e, i) => !(i % 2))) {
   // do something
}

answered Nov 26, 2020 at 4:20

Ayudh

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