display format of input using php

Question

I need to display array of 10 numbers in three columns. if i add another number some like, 11 it must add below 10. as numbers increasing row can be increased not the column, can any one say?

1 4 7 10
2 5 8
3 6 9

am getting 10 in fourth column, but i need it in third column. and row will get increased like

Three columns means 10 ends up on a row of its own. Why must 11 be displayed under it? Can you show an example? — deceze
– deceze ♦, Commented Jun 29, 2011 at 7:42
I swear the same questions was asked very recently, but I can't find it right now... — deceze
– deceze ♦, Commented Jun 29, 2011 at 7:55
Here you go: How do I distribute values of an array in three columns? Browser history search function FTW. — deceze
– deceze ♦, Commented Jun 29, 2011 at 7:59
was asked by two persons in the same location, any chance it's homework from the same class? :D (I know India is big) — MeLight
– MeLight, Commented Jun 29, 2011 at 8:13

Gaurav Porwal · Accepted Answer · 2011-06-29 09:12:32Z

1

Display Output in table..

<?php
$arr = array("1","2","3","4","5","6","7","8","9","10", "11", "12", "13");

$row= ceil(count($arr)/3);
echo "<table border='1'>";
for($i = 1; $i <= $row; $i++) {
    echo "<tr>";
    echo "<td>". $i ."</td>";
    $k = 0;
    $pre = 0;
  for($j = 1; $j <= 2; $j++) {
    if($pre == 0)
      $pre = $k = $i + $row;
    else
      $pre = $pre + $row;

    if($pre <= max($arr))
      echo "<td>". $arr[$pre-1] ."</td>";
  }
  echo "</tr>";
}
echo "</table>";
?>

Output will be:

answered Jun 29, 2011 at 9:12

Gaurav Porwal

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2 Comments

jeni Over a year ago

instead of writing the enitre array like this $arr = array("1","2","3","4","5","6","7","8","9","10", "11", "12", "13");, u can use $arr = range(1,13);

Gaurav Porwal Over a year ago

good suggestion. but here my goal was to display data in desired format.

Gaurav Porwal · Accepted Answer · 2011-06-29 08:48:44Z

0

Try this...

<?php
$arr = array("1","2","3","4","5","6","7","8","9","10", "11", "12", "13", "14");

$row= ceil(count($arr)/3);

for($i = 1; $i <= $row; $i++) {
    echo $i;
    $k = 0;
    $pre = 0;
  for($j = 1; $j <= 2; $j++) {
    if($pre == 0)
      $pre = $k = $i + $row;
    else
      $pre = $pre + $row;

    if($pre <= max($arr))
      echo " ". $arr[$pre-1] ." ";
  }
  echo "<br>";
}

?>

Output when 14 element:

Output when 11 element:

Output when 13 element:

answered Jun 29, 2011 at 8:48

Gaurav Porwal

5134 silver badges6 bronze badges

1 Comment

Gaurav Porwal Over a year ago

yes jeni very easy.. I add new answer that add result in table.

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