How can I delete a dictionary object using python? [duplicate]

Question

I've got a dictionary that I am trying to remove a specific object.

{
  "authorizationQualifier": "00",
  "testIndicator": " ",
  "functionalGroups": [
    {
      "functionalIdentifierCode": "SC",
      "applicationSenderCode": "6088385400",
      "applicationReceiverCode": "3147392555",
      "transactions": [
        {
          "name": null,
          "transactionSetIdentifierCode": "832",
          "transactionSetControlNumber": "000000001",
          "implementationConventionReference": null,
          "segments": [
            {
              "BCT": {
                "BCT01": "PS",
                "BCT03": "2",
                "id": "BCT"
                     }
             }
           ]
         }
       ]
     }
   ]
}

I'm trying to delete the "segments" list of objects while keeping the functional groups and transactions lists.

I've tried,

ediconverted = open("converted.json", "w")
with open('832.json','r') as jsonfile:
    json_content = json.load(jsonfile)

for element in json_content:
    element.pop('segments', None)

with open('converted.json', 'w') as data_file:
    json_content = json.dump(json_content, data_file)

I used loads() to deserialize the json file to a dictionary. Then I can get each list key by using - shortdata = data["functionalGroups"][0]["transactions"][0] (data being the deserialized json file); however I am unclear on how to remove the segments list. Ive tried .pop with no luck — sal
– sal, Commented Dec 16, 2020 at 16:14

IoaTzimas · Accepted Answer · 2020-12-16 16:14:03Z

1

For this specific structure, let's name it d, the following will work:

del d["functionalGroups"][0]["transactions"][0]["segments"]

edited Dec 16, 2020 at 16:14

answered Dec 16, 2020 at 16:06

IoaTzimas

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Comments

user2390182 · Accepted Answer · 2020-12-16 16:07:18Z

1

Assuming you want to remove it for all the groups and transactions:

for g in data["functionalGroups"]: 
    for d in g["transactions"]: 
        d.pop("segments")
        # or, if segments is an optional key
        d.pop("segments", None)

You could do del d["segments"] which has a little less overhead as it does not return anything, but it doesn't offer the option to smoothly handle the case where "segments" is not present (as does dict.pop).

answered Dec 16, 2020 at 16:07

user2390182

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1 Comment

sal Over a year ago

This one did it as well, thank you!

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