Python Regex to replace each character in group

Question

Say I have a string like so

txt = 'Source_Test_MyStuff_v001.0746.exr'
name = re.sub(r'\.([0-9]+)\.', '#', txt )

Outputs:

Source_Test_MyStuff_full_v001#exr

My goal is to find the group containing only numbers between the two periods .. and replace each number within the periods (.) with pound signs.

The desired result is this... Outputs:

Source_Test_MyStuff_full_v001.####.exr

Other examples that could occur:

Source_Test_MyStuff_v001.0586006.exr >> Source_Test_MyStuff_v001.#######.exr
Source_Test_MyStuff_v001.76.exr >> Source_Test_MyStuff_v001.##.exr

How can i achieve this with python and regex?

Wiktor Stribiżew · Accepted Answer · 2020-12-16 17:48:20Z

2

You can use

re.sub(r'(?<=\.)[0-9]+(?=\.)', lambda x: '#'*len(x.group()), txt )

The (?<=\.)[0-9]+(?=\.) regex match one or more digits only when they are enclosed with dot chars on both ends, and lambda x: '#'*len(x.group()) replaces the matches with the same amount of # chars as the match length.

See a full Python demo:

import re
txt = 'Source_Test_MyStuff_v001.0746.exr'
print( re.sub(r'(?<=\.)[0-9]+(?=\.)', lambda x: '#'*len(x.group()), txt ) )
# => Source_Test_MyStuff_v001.####.exr

answered Dec 16, 2020 at 17:48

Wiktor Stribiżew

631k41 gold badges502 silver badges633 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Python Regex to replace each character in group

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related