How to solve Jacobian elliptical function in python

Question

I know how to solve in Mathematica with EllipticF:

EllipticF[ζI[P], k2[P]] - EllipticF[ζr[P, r], k2[P]]

That's basically what i want to do in Python. I've tried many thing to use such as the function scipy.special.ellipj, but it returns a list and i want a number. Please, does anyone know how to solve this problem?

Please provide a minimal reproducible example, as well as the current and expected output. — AMC
– AMC, Commented Dec 24, 2020 at 1:46

Warren Weckesser · Accepted Answer · 2020-12-24 17:00:12Z

1

The equivalent to Mathematica's EllipticF in SciPy is scipy.special.ellipkinc.

For example, in Wolfram Alpha, EllipticF(3/4, 1/10) gives the numerical value 0.7564213553633020688976920....

With SciPy,

In [49]: from scipy.special import ellipkinc                                                                                               

In [50]: ellipkinc(0.75, 0.1)                                                                                                              
Out[50]: 0.7564213553633021

(I don't know what the arguments are that you are passing to EllipticF, so I can't help you with those.)

answered Dec 24, 2020 at 17:00

Warren Weckesser

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