How to display values for office in JSON records via PHP [duplicate]

Question

I am trying to display JSON records. I have successfully gotten values for id, chart_id, first_name.

My issue is that values for office parameters throws error of undefined offset. How do I also print values for offices parameters?

Below is the code:

<?php

$output ='
{"previous":null,"results":[
{"id":91168488,"chart_id":"SMAM000001", "offices":[3033],"first_name":"Nancy"},
{"id":91168489,"chart_id":"MADE000004", "offices":[3044], "first_name":"Moore"}]
}
';

$json = json_decode($output, true);

foreach($json["results"] as $v1){
    echo $id = $v1['id'];
    echo "<br><br>";

    echo $chart_id = $v1['chart_id'];
    echo "<br><br>";

    echo $first_name = $v1['first_name'];
    echo "<br><br>";
    
    echo $offices = $v1['offices'];
    echo "<br><br>";
}
?>

Good code indentation would help us read the code and more importantly it will help you debug your code Take a quick look at a coding standard for your own benefit. You may be asked to amend this code in a few weeks/months and you will thank me in the end. — RiggsFolly
– RiggsFolly, Commented Dec 29, 2020 at 17:50
maybe $offices = implode(', ', $v1['offices']); would do it since it is an array. — Cornel Raiu
– Cornel Raiu, Commented Dec 29, 2020 at 17:54
The brackets around [3033] in "offices":[3033] makes that another array :) — RiggsFolly
– RiggsFolly, Commented Dec 29, 2020 at 17:55
Thanks everyone. special Thanks to you Stefan. your suggestions works for me. you can update it as the right answer. — Nancy Moore
– Nancy Moore, Commented Dec 29, 2020 at 17:56

Stefan Avramovic · Accepted Answer · 2020-12-29 17:58:22Z

2

Since [3033] is an array, just add [0] at the end of $v1['offices']

echo $offices = $v1['offices'][0];

answered Dec 29, 2020 at 17:58

Stefan Avramovic

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