Trying to convert List[String] into List[Int] based on a Map.
However if the key does not exist I will get a null pointer exception.
How to handle that?
val strList = ["a","b","not exist in map" ]
val myMap = Map(
"a" -> 1,
"b" -> 2
)
var myList = new ListBuffer[Int]()
strList.foreach(k =>
myList += myMap(k)
)
myList.toList
This assumes that any List entry that isn't a Map key should just be ignored.
val strList = List("a", "b", "not exist in map")
val myMap = Map("a" -> 1, "b" -> 2)
val myList = strList.flatMap(myMap.get)
//myList: List[Int] = List(1, 2)
The order of results, myList, is determined by the order of keys found in strList.
The proposed solution works perfectly, but for completeness I'd like to add the following:
val strSet = Set("a", "b", "not exist in map")
val myMap = Map("a" -> 1, "b" -> 2, "c" -> 3)
val myList = myMap.view.filterKeys(strSet).values.toList
//myList: List[Int] = List(1, 2)
This solution's complexity is linear with respects to the number of items in the map, whereas strList.flatMap(myMap.get) is linear with respects to the number of items in the list.
Note that I used a Set instead of a List, otherwise the complexity would have been quadratic. Note further that I used the set itself as a predicate (more about it in the Scala API docs, here for version 2.13.4).
You can play around with this solution here on Scastie.
val intList = strList.map(s => myMap.get(x))which will return a List of Options which represent that some values do not exists so you can deal with that latter, you can also do this:val intList = strList.map(x => myMap.getOrElse(key = x, default = 0))if you wan to provide a default value (in this case zero, but you can use what you want) for missing keys. Or if you want to remove / skip missing values doval intList = strList.flatMap(x => myMap.get(x)).myMap.filter(x=>strList.contains(x._1)).map(_._2)