So for example: 0 10 11 100 101 110 111
And so on.
I would like to have it go infinitely, but that might not be possible. I have already tried this:
lista = [1,2,3,4,5,6,7,8,9,10]
listres = [str(bin(x))[2:].zfill(4) for x in lista]
print(listres)
And it works, but it is all one line, and also not infinite.
You could create a generator:
def infinite_binary():
x = 0
while True:
yield str(bin(x))[2:]
x += 1
infinite_binary_gen = infinite_binary()
while True:
print(next(infinite_binary_gen))
Output:
0
1
10
11
100
101
110
111
1000
1001
... and so on
As mentioned in @chepner's comment you can use itertools.count(start=0, step=1) for the base generator:
from itertools import count
infinite_binary_gen = (str(bin(x))[2:] for x in count())
while True:
print(next(infinite_binary_gen))
itertools.count already provides the base generator needed. infinite_binary_gen = (str(bin(x))[2:] for x in count()).Use a loop like this instead of a list comprehension:
i = 0
while True:
# uncomment this line to break the infinite loop:
# if i > 10: break
print(str(bin(i))[2:])
i += 1
Note that zfill(4) is not needed here.
If you need to cast the result to
int, use: print(int(str(bin(i))[2:]))
I would just use a while loop. This way, you could do it in 4 lines of code. Try this:
count = 1
while True:
listres = str(bin(count))[2:].zfill(4)
print(listres)
count += 1
while True: digit = random.choice([0,1])