How do you convert seconds (array) since specific time in Python?

Question

I try to convert second data since 1993/01/01 like this

time = [7.57382412e+08, 7.57382436e+08, 7.57382461e+08, ...,
   7.88918357e+08, 7.88918381e+08, 7.88918406e+08]

I can convert it one by one like this

datetime.datetime(1993,1,1) + datetime.timedelta(seconds=time[0])

If I enter the array into timedelta

datetime.datetime(1993,1,1) + datetime.timedelta(seconds=time)

It is showing a TypeError:

Traceback (most recent call last):
  File "<input>", line 1, in <module>
TypeError: unsupported type for timedelta seconds component: numpy.ndarray

How can I figure it out ?

Note that Python will treat the starting point as local time if you don't set a time zone (e.g. as UTC, tzinfo=datetime.timezone.utc). — FObersteiner
– FObersteiner, Commented Jan 7, 2021 at 6:39

Vinay Kurmi · Accepted Answer · 2021-01-07 06:36:23Z

1

Try using list comprehension as below:

[datetime.datetime(1993,1,1) + datetime.timedelta(seconds=each) for each in time]

answered Jan 7, 2021 at 6:36

Vinay Kurmi

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