PHP: How to pass array as argument to receiving function that uses func_get_args?

Question

I'm having a problem with getting an array (with all its data) over to a receiving function. I am passing the array over as a constructor argument ($myarray):

$s = new MyQuery($param1, $myarray);

The receiving side is a MyQuery object receiving the arguments, using:

$a = func_get_args();

But it does not give me the values in the array: If I do:

$size=func_num_args();
$a=func_get_args();
for ($i=0;$i<$size;$i++) {
    if (is_array($a[$i])){
        $arr = $a[$i]; //trying to get the very array....
        echo ($arr[0]);
    }
}

.. the echo here does just say "Array". Does it have to do with the func_get_args() function? Very thankful for any help.

The printed string "Array" indicates that $arr[0] is an array itself. Try var_dump($arr[0]); instead to better understand what you're accessing. — stlvc
– stlvc, Commented Jan 19, 2021 at 10:12
Thank you very much! var_dump ($a[$i]) gives: array(1) { [0]=> array(1) { [0]=> string(3) "cat" } } Now I am one step further! How to access "cat" directly? — Perry J
– Perry J, Commented Jan 19, 2021 at 10:35

azibom · Accepted Answer · 2021-01-19 10:49:00Z

1

Try this code:

<?php

function foo()
{
    $argsCount = func_num_args();
    $args=func_get_args();
    for ($i = 0; $i < $argsCount ; $i++) {
        if (is_array($args[$i])){
            print_r($args[$i]);
        }
    }
}

foo(1, 2, [3]);   
?>

output

Array
(
    [0] => 3
)

answered Jan 19, 2021 at 10:49

azibom

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4 Comments

Perry J Over a year ago

Thank you very much! At least, by using var_dump and print_r, I see the array data is actually there. But I cannot use it like that.I must be able to get at that value directly, what is the syntax? var_dump ($a[$i]) gives: array(1) { [0]=> array(1) { [0]=> string(3) "cat" } } I cant use var_dump in my real app. I want to get "cat" as a value to use.

azibom Over a year ago

try this $a[$i][0][0]

Perry J Over a year ago

SPLENDIDO!!!!! Great! Thank you very much for help!

azibom Over a year ago

You're welcome, if my answer helped you with your question, I would appreciate it if you upvote my answer and choose it as the best answer as you wish.

mbesson · Accepted Answer · 2021-01-19 10:15:54Z

0

Actually you should be able to get you array with this piece of code

But echo can't print the full array.

Try replacing echo ($arr[0]); by var_dump($arr); or print_r($arr);

answered Jan 19, 2021 at 10:15

mbesson

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