Printing Array of objects more concisely

Question

I'm creating an array of objects and having an issue in printing this easily

Dog Dogobj[]=new Dog[2]; // Dog objects within this array
Dogobj[0] = new Dog(Age, weight, name); 
Dogobj[1] = new Dog(Age, weight, name);

System.out.println("Dog age?: "+Dogobj[0].Dogtype etc.)

Now after creating these I can't find an easy way of printing these that isn't a lot of long lines. This is the only way I have found I can do it (above)- there are about 10 variables for each object so they are very long lines.

Have you added a toString() method to your Dog class?

khelwood
– khelwood

2021-01-19 13:09:31 +00:00
Commented Jan 19, 2021 at 13:09 — khelwood
– khelwood, Commented Jan 19, 2021 at 13:09

javadev · Accepted Answer · 2021-01-19 19:53:15Z

2

You may do something like:

for (Dog dog : Dogobj) {
    System.out.println(dog); // This way every dog will be printed in a new line
}

And of course, implement Dog's toString method.

in "Dog" class definition:

@Overrride
public String toString() {
    "Age: " + age + "," +
    "weight: " + weight + ","
    "name: " + name;
}

if you want every dog's member will be printed in a new line, you may implement toString that way:

@Overrride
public String toString() {
    "Age: " + age + ",\n" +
    "weight: " + weight + ",\n"
    "name: " + name;
}

edited Jan 19, 2021 at 19:53

answered Jan 19, 2021 at 13:09

javadev

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Comments

Roshin Raphel · Accepted Answer · 2021-01-19 13:40:35Z

1

Implement toString() method in your DogObj class. Inside this method you can return a string that needs to be printed from the object.
Print the objects inside a for loop.

    for (int i = 0; i < Dogobj.length; i++) {
               System.out.println(DogObj[i]);
           }

edited Jan 19, 2021 at 13:40

Roshin Raphel

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answered Jan 19, 2021 at 13:13

user3364183

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Comments

AngryParticle · Accepted Answer · 2021-01-20 07:14:03Z

1

Use this:

  `for(String d : dog)`

List item:

{System.out.println(d);}
Or this:

for(int i=0 ; i<dog.length ; i++){ System.out.println(dog[i]);}

edited Jan 20, 2021 at 7:14

AngryParticle

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answered Jan 19, 2021 at 22:22

A_Gour

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