Regex[Python] Extract from url path parameters

Question

I have an URLs from the access log. Example: /someService/US/getPersonFromAllAccessoriesByDescription/67814/alloy%20nudge%20w

/someService/NZ/asdNmasdf423-asd342e/getDealerFromSomethingSomething/FS443GH/front%20parking%20sen

I cannot make any assumption on the service name or the function name.

I'm trying to find a regex that can only match in the first log:

67814
alloy%20nudge%20w

and in the second:

asdNmasdf423-asd342e
FS443GH
front%20parking%20sen

with some heuristic, I tried to use [a-zA-Z0-9_%-]{15,}|[A-Z0-9]{5,} match only long strings but the function names(getPersonFromAllAccessoriesByDescription, getDealerFromSomethingSomething) also had been caught.

I was thinking about regex that can do the same as [a-zA-Z0-9_%-]{15,} but with condition that it must be at least one digit, so this way the function names will be skipped.

Thank you

Ryszard Czech · Accepted Answer · 2021-01-28 23:37:32Z

1

Your heuristics is fine, use

\b(?=[a-zA-Z_%-]*[0-9])[a-zA-Z0-9_%-]{5,}

See proof.

Explanation

--------------------------------------------------------------------------------
  \b                       the boundary between a word char (\w) and
                           something that is not a word char
--------------------------------------------------------------------------------
  (?=                      look ahead to see if there is:
--------------------------------------------------------------------------------
    [a-zA-Z_%-]*             any character of: 'a' to 'z', 'A' to
                             'Z', '_', '%', '-' (0 or more times
                             (matching the most amount possible))
--------------------------------------------------------------------------------
    [0-9]                    any character of: '0' to '9'
--------------------------------------------------------------------------------
  )                        end of look-ahead
--------------------------------------------------------------------------------
  [a-zA-Z0-9_%-]{5,}       any character of: 'a' to 'z', 'A' to 'Z',
                           '0' to '9', '_', '%', '-' (at least 5
                           times (matching the most amount possible))

answered Jan 28, 2021 at 23:37

Ryszard Czech

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2 Comments

Alex Over a year ago

Works perfectly, I tried with lookahead but without \b. Thank you for help

Ryszard Czech Over a year ago

@Alex Please kindly accept the answer by clicking the grey tick on the left.

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