Open a browser in Python

Question

I have a list of 3 browsers, with the random choice I want to open a link randomly using one of the browsers in my list, but when I run the code, all browsers get opened.

my_url="URL"
dlist=[webdriver.Edge(),webdriver.Chrome(),webdriver.Firefox()]
web_driver = random.choice(dlist)
web_driver.get(url)
web_driver.quit()

Sayse · Accepted Answer · 2021-02-01 11:48:47Z

3

You're initalizing them all inside the list, just keep a list of the browsers then initialize them when selected

dlist=[webdriver.Edge,webdriver.Chrome,webdriver.Firefox]
web_driver = random.choice(dlist)()

answered Feb 1, 2021 at 11:48

Sayse

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Thomas Weller · Accepted Answer · 2021-02-01 11:49:12Z

2

Since all of the entries in the list have parenthenses, an object will be created immediately, thus opening each browser.

Remove the parenthenses to have the class in the list, not an object.

dlist=[webdriver.Edge , webdriver.Chrome , webdriver.Firefox ]
                     ^                  ^                   ^ do not create an object

Then, create the object later after choosing the class

web_driver = random.choice(dlist)()
                                 ^^ create the object

answered Feb 1, 2021 at 11:49

Thomas Weller

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