Javascript - Regex match issue

Question

I have created this Regex function and it returns false because of the second condition, but I cannot undestand why?

function telephoneCheck(str) {
  if (str.match(/[!?]/) !== null) {
    return false;
  } else if (str.match(/\d/g).length === 11 && str[0] !== 1) {
    return false;
  }
};

console.log(telephoneCheck("1 555-555-5555"));

Please read this page in its entirety, to make sure people can best help answer your questions. stackoverflow.com/help/how-to-ask — Andy Ray
– Andy Ray, Commented Feb 9, 2021 at 7:36
This is a syntax here because of extra ( after function. function(telephoneCheck(str) Please make sure to post compilable code. — adiga
– adiga, Commented Feb 9, 2021 at 7:39

Andy Ray · Accepted Answer · 2021-02-09 07:35:20Z

2

str[0] will be the string "1", and you're checking if it equals the number 1. Using === or !== compares the types of the variables as well as the values.

You want str[0] !== "1"

answered Feb 9, 2021 at 7:35

Andy Ray

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1 Comment

Mohammad Mostafa Dastjerdi Over a year ago

also you can use != or ==. that type isn't a factor in comparison

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