Lambda and vectorize in python

Question

I'm learning data analysis while performing vectorized operation with lambda function it run at first but again run it shows error as TypeError: <lambda>() takes 1 positional argument but 2 were given

sample data of tips.csv file

quality = lambda x:'Generous' if x['tip']/x['total_bill']>0.25 else 'Other'

This is the image that I run first which doesn't show any error

a = np.vectorize(quality)
df['q2'] = a(df['total_bill'],df['tip'])
df['q1'] = np.vectorize(quality)(df['total_bill'],df['tip'])

jezrael · Accepted Answer · 2021-02-11 09:51:27Z

1

You can vectorize solution different way - with numpy.where instead lambda and np.vectorize:

df['q1'] = np.where(df['tip']/df['total_bill']>0.25, 'Generous' ,'Other')

EDIT:

After some research for correct working need pass x, y to lambda and also change selecting by columns in lambda function like, because you pass 2 columns to function:

df = pd.DataFrame({
    'tip':[1,2,6],
    'total_bill':[1,5,1]  })

quality = lambda x, y:'Generous' if x/y>0.25 else 'Other'

a = np.vectorize(quality)
df['q2'] = a(df['total_bill'],df['tip'])
df['q1'] = np.vectorize(quality)(df['total_bill'],df['tip'])
print (df)

   tip  total_bill        q2        q1
0    1           1  Generous  Generous
1    2           5  Generous  Generous
2    6           1     Other     Other

edited Feb 11, 2021 at 9:51

answered Feb 11, 2021 at 9:29

jezrael

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2 Comments

Deepan Over a year ago

Getting answer is not the problem. I just want to know why it's not working now but worked before. This answer is quite great. Thanks for the answer

jezrael Over a year ago

@Deepan - Unfortuantely not idea.

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