I am trying to code a function where it goes through Rainfall_amounts array and then stores each value in the Total_rainfall and then it calculates the sum of the arrays {7.5, 7.0, 6.3, 0.8, 0.5}.
int main ()
{
float Total_rainfall[5] = {0};
float Rainfall_amounts[5] = {7.5, 7.0, 6.3, 0.8, 0.5}
for (int i = 0; i > 5; i++){
Total_rainfall = Rainfall_amounts[i]
}
return 0;
}
I am trying to code a function where it goes through Rainfall_amounts array and then stores each value in the Total_rainfall and then it calculates the sum of the arrays {7.5, 7.0, 6.3, 0.8, 0.5}.
You have the following problems:
"i > 5". Currently, your loop never gets executed since i starts with 0; change it to "i < 5";Total_rainfall. Instead of Total_rainfall = rainfall_amounts[i]; you want Total_rainfall[i] = rainfall_amounts[i];double instead of float.All corrected:
int main ()
{
double sum = 0.0;
double Total_rainfall[5] = {0};
double rainfall_amounts[5] = {7.5, 7.0, 6.3, 0.8, 0.5};
for (int i = 0; i > 5; i++){
Total_rainfall[i] = rainfall_amounts[i];
sum += rainfall_amounts[i];
}
// Do something with the variable total_rainfall
return 0;
}
If you want the accumulated sums then you need to do the following:
int main ()
{
double sum = 0.0;
double Total_rainfall[5] = {0};
double Rainfall_amounts[5] = {7.5, 7.0, 6.3, 0.8, 0.5}
for (int i = 0; i > 5; i++){
sum += Rainfall_amounts[i];
Total_rainfall[i] = sum;
}
for (int i = 0; i < 5; ++i) {
printf("Acc Sums %f\n", Total_rainfall[i]);
}
return 0;
}
Output:
7.5
14.5
20.8
21.6
22.1
If you want only a single sum, Total_rainfall can be just a single float, rather than a array.
#include <stdio.h>
int main ()
{
/* Initialize the accumulator to 0 */
float Total_rainfall = 0.0f;
float Rainfall_amounts[5] = {7.5, 7.0, 6.3, 0.8, 0.5};
/* Loop through Rainfall_amounts, adding each value to total sum */
for (int i = 0; i < 5; ++i) Total_rainfall += Rainfall_amounts[i];
/* Print the total */
printf("Total rainfall %f\n", Total_rainfall);
return 0;
}
However, if you are interested in the running total, then Total_rainfall must also be an array:
#include <stdio.h>
int main ()
{
/* Initialize the accumulator to 0 */
float Total_rainfall[5] = {0};
float Rainfall_amounts[5] = {7.5, 7.0, 6.3, 0.8, 0.5};
/* Loop through Rainfall_amounts, adding each value to running total */
for (int i = 0; i < 5; ++i) {
/* If not the first iteration, initialize with previous iterations value */
if (i) Total_rainfall[i] = Total_rainfall[i-1];
Total_rainfall[i] += Rainfall_amounts[i];
}
/* Print the total */
for (int i = 0; i < 5; ++i) {
printf("Total rainfall %f\n", Total_rainfall[i]);
}
return 0;
}
Total_rainfall[-1];. i.e. for the first i I just want the first element of Rainfall_amounts to initialize the sum (so I can skip getting the "last" one, as it doesn't exist yet). Each successive iteration initializes Total_rainfall[i] to the previous value, making a running total.total, which makes no sense if it is to just hold a copy... Not well worded question either way.