I got this issue.
I want to convert integer 71 (type number) to one decimal, meaning 71.0
but I need it to stay of type number.
Searched and the only solution I found was to use toFixed(1) and then parseFloat on
the result, and that does returns a number but 71, without the decimal.
const float = (num) => {
let fixed = (num).toFixed(1)
let float = parseFloat(fixed)
return float
}
float(71)
How should I do it?
This makes no sense, because an integer (whole number) will almost always equal its floating-point equivalent, unless there is a some odd precision behavior.
71 === 71.071 === 71.0071 !== 71.000000001Did you want to truncate a floating number using precision?
const truncateFloat = (n, p = 0) => parseFloat(n.toFixed(p));
// Truncate an irrational number (PI)
console.log(truncateFloat(Math.PI, 2) === 3.14) // trueRemove the parseFloat(fixed) and keep it as below
const float = (num) => {
let fixed = (num).toFixed(2)
//let float = parseFloat(fixed)
return float
}
float(71)
use toFixed(n) where n is the number of 10th places after the decimal.
You have stated that you need to keep it as number at the end but the thing is, if the decimals are 0, it will always round up to a whole number. So you may want to rather consider adding the toFixed(n) at the point of printing to the screen so they always print with that extra.
========= UPDATE
I just found a cleaner solution. consider the below with a link to the solution
const float = (num) => {
tmp = '0.00';
tmp = (+tmp + num).toFixed(2);
return tmp
}
float(71)
reference: how to get a float using parseFloat(0.00)
parseInt(number) eg: parseInt(71) and you still get a number for your calculation.
71is the same as71.0, which is the same as71.00, etc. JS truncates unnecessary zeroes for display. If you want a specific format, you need a string.71and71.0are exactly the same.71and71.0are the same in this format.