const isIncluded = ["1","2"]
.includes("1") || ["1","2"]
.includes("2") ;
how can I reformat this monstrosity in a more elegant way
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2 Answers
For checking an array with another array, you could iterate one array and check the value with includes.
array.some(v => isIncluded.includes(v))
1 Comment
Bogdan
That looks so much better thank you Nina!
You need something like this?
const checkIncluded = (arr1, arr2) => arr1.some(item => arr2.includes(item));
If any item from arr1 is inside arr2 returns true.
Example:
const isIncluded1 = checkIncluded(["1", "2"], ["1","2"]) // true
const isIncluded2 = checkIncluded(["1", "2"], ["1"]) // true
const isIncluded3 = checkIncluded(["1", "2"], ["2"]) // true
const isIncluded4 = checkIncluded(["1", "2"], ["3", "5"]) // false
