Use Regex with RegExp

Question

I'm writing a Regex to detect if a string starts with a valid protocol —lets say for now it can be http or ftp—. The protocol has to be followed by ://, and one or more characters, with no white spaces in the string, ignoring case.

I have this Regex that is doing everything, except checking for white spaces in the string:

const regex = new RegExp('^(http|ftp)(://)((?=[^/])(?=.+))', 'i');
const urlHasProtocol = regex.test(string);

^(http|ftp) — checks for http or ftp at the beginning
(://) — is followed by "://"
((?=[^/])(?=.+)) — is followed by a string that
   (?=[^/]) — doesnt start with "/"
   (?=.+) — has one or more characters

Those must pass:

http://example.com
http://example.com/path1/path2?hello=1&hello=2
http://a
http://abc

Those must fail:

http:/example.com
http://exampl e.com
http:// exampl e.com
http://example.com // Trailing space
http:// example.com
http:///www.example.com

I'm trying to add the rule for the whitespaces. I'm trying with a look ahead that checks for non one or more white spaces in the middle or at the end: (?=[^s+$])

const regex = new RegExp('^(http|ftp)(://)((?=[^/])(?=.+)(?=[^s+$]))', 'i');
const urlHasProtocol = regex.test(string);

But this is not working properly.

Any advice will be welcome

new RegExp('^(?:ht|f)tp://[^/\\s]\\S*$', 'i') or new RegExp('^(?:ht|f)tp://[^/\\s]+(?:/[^/\\s]+)*/?$', 'i') — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Mar 15, 2021 at 10:02

RavinderSingh13 · Accepted Answer · 2021-03-15 10:38:44Z

5

With your shown samples only, could you please try following.

^(https?|ftp):\/\/(?!\W*www\.)\S+$

Here is the Online demo of above regex

Explanation: Adding detailed explanation for above regex.

^(https?|ftp):  ##Checking if value starts with http(s optional here to match http/https) OR ftp.
\/\/            ##Matching 2 // here.
(?!\W*www\.)    ##Checking a negative lookahead to see if \W matches any non-word character (equivalent to [^a-zA-Z0-9_]) then www with a dot is NOT in further values.
\S+$            ##matches any non-whitespace character will end of the value here.

edited Mar 15, 2021 at 10:38

answered Mar 15, 2021 at 10:32

RavinderSingh13

135k14 gold badges61 silver badges100 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

a.mola · Accepted Answer · 2021-03-15 10:33:54Z

3

Here's my regex for your URL;

I looked for valid URL characters and added them to my Regex

const regex = /^(http|ftp):\/{2}([\w\d]+[-\._~:/?#\[\]@!$&'()*+,;%=]*)*$/i;
const tests = [
  "http://example.com",
  "http://example.com/path1/path2?hello=1&hello=2",
  "http://a",
  "http://abc",
  "http:/example.com",
  "http://exampl e.com",
  "http:// exampl e.com",
  "http://example.com ",
  "http:// example.com",
  "http:///www.example.com"
];

console.log(tests.map(testStr => regex.test(testStr)));

answered Mar 15, 2021 at 10:33

a.mola

4,0119 silver badges23 bronze badges

Collectives™ on Stack Overflow

Use Regex with RegExp

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related