Create a bar graph without using matplotlib

Question

I need to get a 5 digit integer as an input, and convert this integer into a 2D array and print it out as a bar graph. The result I am trying to get is:

If the input is 19683, It should return:

  x
  x   x
  x   x
  x x x
  x x x
  x x x
  x x x x
  x x x x
x x x x x
----------

This is what I have written already

x = int(input("Enter a 5 digit integer: "))
digits = [int(n) for n in str(x)]
rows = max(digits)
bar_graph = [[0] * len(digits) for i in range(rows)]

But I don't know what I should do from here.

I just need to find a way to replace the 0s with the xs and in the right order.

Tomerikoo · Accepted Answer · 2021-03-26 13:58:02Z

1

You started off good. You need to have each digit and to know the maximum digit (you got with rows = max(digits)).

Now all you need to do is loop the rows in decreasing order, and for each digit check if it needs to be marked in this row. This will be true when the digit is greater-than or equal-to the row number:

x = int(input("Enter a 5 digit integer: "))
digits = [int(n) for n in str(x)]
rows = max(digits)
bar_graph = []
for row in range(rows, 0, -1):
    bar_graph.append(['x' if digit >= row else ' ' for digit in digits])
for row in bar_graph:
    print(' '.join(row))
print('-'*(2*len(digits)+3))

But note that it's not really necessary to store everything in a 2D list and you can print directly by iterating the rows and digits:

for row in range(rows, 0, -1):
    print(row, ':', ' '.join(['x' if digit >= row else ' ' for digit in digits]))
print('-'*(2*len(digits)+3))

Will give:

Enter a 5 digit integer: 19683
9 :   x      
8 :   x   x  
7 :   x   x  
6 :   x x x  
5 :   x x x  
4 :   x x x  
3 :   x x x x
2 :   x x x x
1 : x x x x x
-------------

Note that this will always "truncate" the graph to the largest digit, for example:

Enter a 5 digit integer: 11132
3 :       x  
2 :       x x
1 : x x x x x
-------------

If you want the graph to always be "complete" (starting with 9), just change this line:

rows = 9

To get:

Enter a 5 digit integer: 11132
9 :          
8 :          
7 :          
6 :          
5 :          
4 :          
3 :       x  
2 :       x x
1 : x x x x x
-------------

edited Mar 26, 2021 at 13:58

answered Mar 26, 2021 at 13:28

Tomerikoo

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4 Comments

Squishy Over a year ago

Is there a way to do this problem using this piece of code too? bar_graph = [[0] * len(digits) for i in range(rows)]

Tomerikoo Over a year ago

Not sure I understand the question

Squishy Over a year ago

The question without being edited was: Ask the user to enter a 5 digit integer. Convert the integer to a bar graph stored in a 2- dimensional list of characters. Print the bar graph.

Tomerikoo Over a year ago

I don't see the reason to store a 2D list when you can print it directly with a simple loop. Sorry to say but if this is a requirement of the exercise, it is a very bad one and not teaching you good coding habits

PaxPrz · Accepted Answer · 2021-03-26 13:35:09Z

1

Here you go:

number = input("Enter a number: ")
ls = [9-int(x) for x in s]
for i in range(9,0,-1):
    print(i, ':', *[' ' if v>0 else '*' for v in ls])
    ls = [x-1 for x in ls]
print('-'*(len(s)*2+4))

# input: 19683
# Output:
9 :   *      
8 :   *   *  
7 :   *   *  
6 :   * * *  
5 :   * * *  
4 :   * * *  
3 :   * * * *
2 :   * * * *
1 : * * * * *
-------------

answered Mar 26, 2021 at 13:35

PaxPrz

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Comments

Kasra · Accepted Answer · 2021-03-26 13:40:38Z

1

try this:

num = input()
print("\n".join([" ".join([" " if 10-line>int(j) else "x" for j in num]) for line in range(1,10)]))

edited Mar 26, 2021 at 13:40

answered Mar 26, 2021 at 13:35

Kasra

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Comments

Alexander Rakhmaev · Accepted Answer · 2021-03-26 13:49:13Z

1

Come on, and I'll put in my five cents.

x = 196594345345345432

digits = [int(n) for n in str(x)]

for i in reversed(range(1, max(digits) + 1)):
    this_row = ''
    for digit in digits:
        if digit >= i:
            this_row += 'x'
        else:
            this_row += ' '
    print(this_row)

print('-'.rjust(len(digits), '-'))

 x  x             
 x  x             
 x  x             
 xx x             
 xxxx   x  x  x   
 xxxxx xx xx xxx  
 xxxxxxxxxxxxxxxx 
 xxxxxxxxxxxxxxxxx
xxxxxxxxxxxxxxxxxx
------------------

edited Mar 26, 2021 at 13:49

answered Mar 26, 2021 at 13:44

Alexander Rakhmaev

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