unicode as string execute by variables

Question

let testowy = v.za0+v._7a+v._1+v._1+v._13+v._3+v.za0+v._7a+v._1+v._1+v._13+v._12+v.za0+v._7a+v._1+v._1+v._13+v._11+v.za0+v._7a+v._1+v._1+v._14+v._5+v.za0+v._7a+v._1+v._1+v._14+v._10+v.za0+v._7a+v._1+v._1+v._5+v._15+v.za0+v._7a+v._1+v._1+v._5+v._16;

console.log(testowy) // output unicode "\u0061\u006c\u0065\u0072\u0074\u0028\u0029"
eval(testowy) // gives error
eval("\u0061\u006c\u0065\u0072\u0074\u0028\u0029") // OK - alert()

the question is how to make testowy variable to work as a string?

eval("'"+"testowy+"'") // or
eval("\""+"testowy+"\"") // doesn't work

Does this answer your question? "Variable" variables in Javascript? — General Grievance
– General Grievance, Commented Mar 30, 2021 at 14:55
If not, what error are you getting? We don't know what v is. — General Grievance
– General Grievance, Commented Mar 30, 2021 at 15:01
if console.log is writing "\u0061\u006c\u0065\u0072\u0074\u0028\u0029" then the actual string was probably set using escaped slashes - \\u0061\\u006c\\u0065\\u0072\\u0074\\u0028\\u0029. You'll need to parse the string to unicode characters. — phuzi
– phuzi, Commented Mar 30, 2021 at 15:04

phuzi · Accepted Answer · 2021-03-30 15:20:33Z

1

if console.log is writing "\u0061\u006c\u0065\u0072\u0074\u0028\u0029" then the actual string was probably set using escaped slashes -

\\u0061\\u006c\\u0065\\u0072\\u0074\\u0028\\u0029.

You'll need to convert the string of hexadecimal character codes to Unicode characters...

let testowy = v.za0+v._7a+v._1+v._1+v._13+v._3+v.za0+v._7a+v._1+v._1+v._13+v._12+v.za0+v._7a+v._1+v._1+v._13+v._11+v.za0+v._7a+v._1+v._1+v._14+v._5+v.za0+v._7a+v._1+v._1+v._14+v._10+v.za0+v._7a+v._1+v._1+v._5+v._15+v.za0+v._7a+v._1+v._1+v._5+v._16;

console.log(testowy); // outputs \\u0061\\u006c\\u0065\\u0072\\u0074\\u0028\\u0029

testowy = testowy.split('\\u')
    .map(s => {
        // ignore leading empty string.
        if (s !== '')
            return String.fromCharCode(parseInt(s, 16));
    })
    .join('');

console.log(testowy); // outputs alert()

answered Mar 30, 2021 at 15:20

phuzi

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