The current output of my array is:
"10 FOOT", "45 RPM", "9 VOLT", "910D0", "AGUA", "BEAST", "KEN 5", "NEMCO"
What I want is:
"AGUA", "BEAST", "KEN 5", "NEMCO", "9 VOLT", "10 FOOT", "45 RPM:, "910D0"
How do I achieve this?
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why would a number at the end have precedence over sorting alpha numerically? No wait, what has actually that number at the end have anything to do with the question?Roko C. Buljan– Roko C. Buljan2021-04-04 12:24:29 +00:00Commented Apr 4, 2021 at 12:24
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does this post solve your question? stackoverflow.com/questions/18939726/…MWO– MWO2021-04-04 12:25:57 +00:00Commented Apr 4, 2021 at 12:25
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You need to explain more about your sorting criteria...Majed Badawi– Majed Badawi2021-04-04 12:28:46 +00:00Commented Apr 4, 2021 at 12:28
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1Let's clarify a bit, is this what you want? If an element starts with a letter, sort it alphabetically. If it starts with a number, sort it by the value of the number (not only the first digit), and finally, those starting with a number should go after the ones starting with a letter?blex– blex2021-04-04 12:30:35 +00:00Commented Apr 4, 2021 at 12:30
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Please post compilable code. Those quotes throw an error.adiga– adiga2021-04-04 12:31:27 +00:00Commented Apr 4, 2021 at 12:31
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4 Answers
You could check if the string starts with a digit and sort the rest by groups.
const array = ['10 FOOT', '45 RPM', '9 VOLT', '910D0', 'AGUA', 'BEAST', 'KEN 5', 'NEMCO'];
array.sort((a, b) => isFinite(a[0]) - isFinite(b[0])
|| a.localeCompare(b, undefined, { numeric: true, sensitivity: 'base' })
);
console.log(array);
Comments
const order = ["10 FOOT", "45 RPM", "9 VOLT", "910D0", "AGUA", "BEAST", "KEN 5", "NEMCO"];
order.sort((a, b) => /^[0-9]/.test(a) - /^[0-9]/.test(b) || a.localeCompare(b, undefined, { numeric: true }));
console.log(order);Sort elements starting with a number first, afterwards use localeCompare's numeric option (which ensures "10" > "2").
Comments
You could create 2 new arrays, sort them and put them back together:
const arr = ["10 FOOT", "45 RPM", "9 VOLT", "910D0", "AGUA", "BEAST", "KEN 5", "NEMCO"];
const nums = arr.filter(a => parseInt(a))
const words = arr.filter(a => !parseInt(a))
nums.sort((a,b) => parseInt(a) -parseInt(b))
words.sort()
const finalArray = words.concat(nums)
Comments
const arr = ["10 FOOT", "45 RPM", "9 VOLT", "910D0", "AGUA", "BEAST", "KEN 5", "NEMCO"];
const customCompare = (a, b) =>
/^\d/.test(a) - /^\d/.test(b) ||
a.localeCompare(b, undefined, { numeric: true });
const sorted = arr.sort(customCompare);
console.log(...sorted);