I have an array of number like this
number = [4, -1, 6, -2, 3, 5, -7, 7]
Is there any way to split it when meets negative value?
So, it will be like this
array = [[4], [-1], [6], [-2], [3,5], [-7], [7]]
I think it can be done using regex, but I still not found it
Thanks
First create a few temporary arrays to hold the value(s).
Loop through your main array.
Then check if the number is greater than zero.
Add the positive number to the newly created temporary array.
Also, check for the last element and push it into the output array as required.
In the else part check for the element less then zero
Then first, push the temporary array for positive number into in output array.
After that push the negative number temporary array for negative numbers.
Push that temporary array for negative numbers into the output array.
Now, reset the temporary array for both positive and negative numbers.
let number = [4, -1, 6, -2, 3, 5, -7, 7];
let array = [];
let tempArr = [];
let tempArrForNeg = [];
let numberLength = number.length;
for(let i = 0; i < numberLength; i++){
if(number[i] > 0){
tempArr.push(number[i]);
if(i === (numberLength - 1))
array.push(tempArr);
}
else{
array.push(tempArr);
tempArrForNeg.push(number[i]);
array.push(tempArrForNeg);
tempArr = [];
tempArrForNeg = [];
}
}
console.log(array);
//[[4], [-1], [6], [-2], [3,5], [-7], [7]]Try this:
var number= [1,-2,5,6,2,-2,-3,-4,5];
console.log(splitByPositivity(number));
function splitByPositivity(numArr) {
var newArr = []
var tempArr = [numArr[0]];
for (var i=1;i<numArr.length;i++){
if (numArr[i]>0&&tempArr[tempArr.length-1]>0||numArr[i]<0&&tempArr[tempArr.length-1]<0)
tempArr.push(numArr[i])
else{
newArr.push(tempArr)
tempArr = [numArr[i]];
}
}
newArr.push(tempArr);
return newArr;
}Pay attention you need to handle 0 value. It is not nagitive and not positive
