Using the below I can match all the items in an array but I can only replace the matched values which is expected. Is there a way do do the same but instead of a straight replace, wrap the matched text with specified values?
$colours = array("Red", "Blue", "Green");
$string = "There are three Red and Green walls.";
echo str_replace($colours, "?", $string);
There are three ? and ? walls.
There are three %1%Red%2% and %1%Green%2% walls.
Depending on whether you want to account for context or not, the solutions will vary.
If you plan to just match the strings as is in any context and repalce with their copies enclosed with %1% and %2%, you need to use
preg_replace("/" . implode("|", array_map(function($i) {return preg_quote($i, "/");}, $colours)) . "/", '%1%$0%2%', $string)
The regex is formed here using | OR operator and all special chars in the items in the $colours array are escaped with \ using preg_quote function. The $0 in the replacement refers to the whole match value.
If $colours are phrases with whitespaces, you would need to sort the items so that the longer strings come first:
rsort($colours, SORT_FLAG_CASE | SORT_STRING);
echo "\n" . preg_replace("/" . implode("|", array_map(function($i) {return preg_quote($i, "/");}, $colours)) . "/", '%1%$0%2%',$string);
If these $colours are simple English letter words, and you want to match them as whole words, you do not need preg_quote and you can use word boundaries, like:
preg_replace("/\b(?:" . implode('|', $colours) . ")\b/", '%1%$0%2%', $string)
To make the search case-insensitive, add i flag after last / regex delimiter in the preg_replace first argument.
See the PHP demo:
$colours = array("Red", "Blue", "Green");
$string = "There are three Red and Green walls.";
echo preg_replace("/" . implode("|", array_map(function($i) {return preg_quote($i, "/");}, $colours)) . "/", '%1%$0%2%', $string);
// => There are three %1%Red%2% and %1%Green%2% walls.
echo "\n" . preg_replace("/\b(?:" . implode('|', $colours) . ")\b/", '%1%$0%2%', $string);
// => There are three %1%Red%2% and %1%Green%2% walls.
$colours = array("Red", "Blue", "Green", "Blue jeans");
$string = "There are three Red and Green walls and Blue jeans.";
rsort($colours, SORT_FLAG_CASE | SORT_STRING);
echo "\n" . preg_replace("/" . implode("|", array_map(function($i) {return preg_quote($i, "/");}, $colours)) . "/", '%1%$0%2%',$string);
// => There are three %1%Red%2% and %1%Green%2% walls and %1%Blue jeans%2%.
"/\b(?i:" . implode('|', $colours) . ")\b/"
i flag, "/\b(?:" . implode('|', $colours) . ")\b/i"i think you could do with array_map. Here is my example :
$colours = array("Red", "Blue", "Green");
$string = "There are three Red and Green walls.";
$func = function($value) use ($colours){
return in_array($value, $colours) ? "%1%". $value ."%2%" : $value;
};
$text = array_map($func, explode(" ", $string));
$text = implode(" ", $text);
echo $text; `
What you want is preg_replace. You will be able to replace the matches with a string that includes the match. In this case "%1%$0%2%" where $0 will be replaced with the match.
However, you will need to quote (with preg_quote) and add delimiters to the members of your array. We can do that with array_map.
This is the code:
echo preg_replace
(
array_map
(
function($input)
{
return "/".preg_quote($input, "/")."/";
},
$colours
),
"%1%$0%2%",
$string
);
No, I do not suggest to assume they are safe to use without quoting, even if in this case they are. Yes, creating a single regex pattern with them is viable, but why bother?
simplest but not most effective:
$colours = array("Red", "Blue", "Green");
$colours_replacment = array('%1%Red%2%', '%1%Blue%2%', '%1%Green%2%');
$string = "There are three Red and Green walls.";
echo str_replace($colours, $colours_replacment, $string);
simple and more effective:
$colours = array("Red", "Blue", "Green");
$string = "There are three Red and Green walls.";
foreach($colours as $colour) {
$string = str_replace($colour, '%1%' . $colour . '%2%', $string);
}
echo $string;
%1%…%2%each.preg_replace("/\b(?:" . implode('|', $colours) . ")\b/", '%1%$0%2%', $string)? 3v4l.org/9077N