How to get variable out of a nested loop?

Question

My question is very simple how can I get the result variable out of this nested loop:

for row in new_matrix:
    for col in row:
        if col == 'S':
            result = [(new_matrix.index(row), row.index(col))]

I tried assigning a global variable result above and set it equal to this expression [(new_matrix.index(row), row.index(col))] but it didn't work, I want to do it without using global because it's bad practice

if you do not want to look further,just use break to finish the loop — Juraj Bezručka
– Juraj Bezručka, Commented Apr 7, 2021 at 21:29
Assigning a default value to a variable and then changing it inside a a (nested) loop is not what is meant about avoiding global variables — which are variables defined outside of a function or method whose values get changed inside one. Here's more information. In other words, your code is basically fine except for assigning an initial value to the variable before entering the loops which in your case that didn't work because row and col are only defined inside them. The fix is to simply use None instead. — martineau
– martineau, Commented Apr 7, 2021 at 22:25

Vedhas Deshpande · Accepted Answer · 2021-04-07 21:32:22Z

1

Lists are mutable in python, so you can do this way:

result = []
for row in new_matrix:
   for col in row:
      if col == 'S':
         result.append(new_matrix.index(row), row.index(col))

answered Apr 7, 2021 at 21:32

Vedhas Deshpande

668 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

peter · Accepted Answer · 2021-04-07 21:32:39Z

1

def your_function():
    for row in new_matrix:
        for col in row:
            if col == 'S':
                return [(new_matrix.index(row), row.index(col))]

result = your_function()

answered Apr 7, 2021 at 21:32

peter

7865 silver badges19 bronze badges

Collectives™ on Stack Overflow

How to get variable out of a nested loop?

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related