Remove every second comma from string (python)

Question

I would like to remove every second occurence of a comma in my string but starting from the second comma. My string: "30, 20, 40, 50" and I would like my result to be: "30 20, 40 50" So far I have been using regular expressions to try and achieve this by the following reg sub: myString = re.sub('(,[^,])*,', r'\1', myString) but this results in: "30, 20 40, 50". I hope someone can help me out here.

I got "30 20 40 50" for this expression and not "30, 20 40, 50" on my machine. — Jérôme Richard
– Jérôme Richard, Commented Apr 13, 2021 at 8:10
Please stop editing the thread with mistakes. Leave it as is and move on, thank you. — user15227672
– user15227672, Commented Apr 14, 2021 at 13:17

blhsing · Accepted Answer · 2021-04-13 08:10:30Z

5

You can group the non-comma characters and the optional following comma for preservation instead:

myString = re.sub(',([^,]*,?)', r'\1', myString)

Demo: https://replit.com/@blhsing/EminentWholeOctagons

answered Apr 13, 2021 at 8:10

blhsing

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user15227672 Over a year ago

Will mark your response as the solution as it managed to do the same. Thanks.

user15227672 · Accepted Answer · 2021-04-13 16:53:50Z

0

Thanks to those that responded. My own solution meanwhile ended up being: myString = re.sub(',([^,]*[,]*)', r'\1', myString)

answered Apr 13, 2021 at 16:53

user15227672

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