How to convert a string to an array containing each character in Haskell?

Question

I was looking at this post here: Haskell get character array from string?

I see it says that in haskell strings are essentially arrays containing each letter, but I was wondering; how would I turn the format from the string to an array of individual components, for example:

["ABCD","EFGH"]

to

[["A","B","C","D"],["E","F","G","H"]]

I'd like to know a method without using any external imports.

Strings are lists of Char, not arrays. And ["E","F","G","H"] is a list of String, not an array. Just to avoid future confusion. — David Fox
– David Fox, Commented Apr 13, 2021 at 18:21

willeM_ Van Onsem · Accepted Answer · 2021-04-13 16:13:54Z

2

You can wrap each element in a singleton list, so:

map (map pure) ["ABCD", "EFGH"] :: [[String]]

this then produces:

Prelude> map (map pure) ["ABCD", "EFGH"] :: [[String]]
[["A","B","C","D"],["E","F","G","H"]]

That being said, a String is simply a list of Chars, indeed:

type String = [Char]

so if you just want to work with a list of Chars, you can simply work with the string directly. By converting it to a list of list of Strings, we know that all these strings contain one Char, but that is no longer guaranteed by the type.

answered Apr 13, 2021 at 16:13

willeM_ Van Onsem

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