float << operation by setting the precision for both integer part and float part

Question

I would like to print floating point numbers in a format like this.

01234.56

I use the following function to round a float to n digits.

double round(double val, int precision)
{
    std::stringstream s;
    s << std::setprecision(precision) << std::setiosflags(std::ios_base::fixed) << val;
    s >> val;
    return val;
}

And the following line to output any number with leading zeroes to a fixed length.

setfill ('0') << setw(5) << number

But when I try to combine the two, I end up with non-consistent length, like in the following examples:

8.2 => 008.2
4.57 => 04.56

What I would like to have is an output like this:

8.2 => 08.20
4.57 => 04.57

Can you show me a function like string myround (double d, intpart n, floatpart f) which returns:

myround (1234.5, 5, 2) => 01234.50
myround (1234.569, 5, 2) => 01234.57

I imageine it has been asked before, but I couldn't find it using the internal search engine.

Christian Goltz · Accepted Answer · 2011-07-16 21:03:57Z

2

the fixed manipulator will do the trick I think, my example below outputs what you wanted:

#include <iostream>
#include <iomanip>
using namespace std;
int main(void) {
    cout << setprecision(2) << setfill ('0') << setw(5) << fixed << 8.2 << endl;
    cout << setprecision(2) << setfill ('0') << setw(5) << fixed << 4.57 << endl;
}

just put it into your stringstream and it should work. However, the fixed information will be lost when the string is converted to a double value again. I think it is no good idea to round a float using a string method.

answered Jul 16, 2011 at 21:03

Christian Goltz

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