In CoffeeScript, how can you make a function call with anonymous functions as parameters?

Question

The following gives a syntax error related to the anonymous function:

my_function = (f, x, str) ->
  alert str + f(x)

my_function (x) -> 1 + x, 12, "The answer is: "

The following works:

my_function = (f, x, str) ->
  alert str + f(x)

increment = (x) -> x + 1

my_function increment, 12, "The answer is: "

Duplicate of stackoverflow.com/questions/6463052/…. See also stackoverflow.com/questions/6459630/… — Trevor Burnham
– Trevor Burnham, Commented Jul 17, 2011 at 3:03

Florian Mayer · Accepted Answer · 2011-07-16 22:44:42Z

3

my_function ((x) -> x + 1), 12, "The answer is: "

That should fix it.

answered Jul 16, 2011 at 22:44

Florian Mayer

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