Automate Loop based in how many the user want in python

Question

My professor asked me to simulate Boolean Gates and the output is a truth table

To simulate an n=3 Gates you need 3 for loop

for i in range(0,2):
     for j in range(0,2): 
           for k in range(0,2):
                 stuff

To simulate an n=2 Gates you need 2 for loop

for i in range(0,2):
     for j in range(0,2): 
                 stuff

i wanted to have an an n= user input, so there may be a chance where the user input more than 10 is there a way to automate the loop??

if there's any reference, especially if it uses an oop paradigm, it would be very helpfull Thank you

if I understand you, n changes the loop count by 2**n, if so you can just change the loop range by that equation. unless you use the loop count in stuff — Harry Kruger
– Harry Kruger, Commented Apr 22, 2021 at 13:52

Pietro · Accepted Answer · 2021-04-22 14:01:43Z

4

It looks like you want to generate all the possible 2**n combinations of values for i,j,k,.... If that is the case, you can use itertools.product to generate them all:

from itertools import product

for p in product(range(2), repeat=3):
    print(p)

Which will produce:

(0, 0, 0)
(0, 0, 1)
(0, 1, 0)
(0, 1, 1)
(1, 0, 0)
(1, 0, 1)
(1, 1, 0)
(1, 1, 1)

Simply change repeat=n and you are done.

Cheers!

answered Apr 22, 2021 at 14:01

Pietro

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