Regex to find substring and wrap it in tags - Java [duplicate]

Question

I'm trying to write code which finds all words that are in the following format

"some text":

So alphanumeric characters which are within " symbols and which end with the : symbol. My goal once I find these is to remove the " character and wrap the entire string in tag. So after the code has run, the above text would look like this,

<strong>some text:</strong>

So I believe the regex to find such text for wrapping is the following (formatted for Java),

(\".*?\"):{1}

And by using the following code, I should be able to iterate through all the matches.

Pattern pattern = Pattern.compile("(\".*?\"):{1}");
Matcher matcher = pattern.matcher(stringToSearch);

while(matcher.find()) {
  String matchedGroup = matcher.group();
  matchedGroup = matchedGroup.replaceAll("\"", "");
  matchedGroup = "<strong>" + matchedGroup + "</strong>";
  
  // now what?
}

So I probably went about that all wrong.

Now that I've wrapped the word I wanted in a strong tag, how do I "put it back" where it was?

Tim Biegeleisen · Accepted Answer · 2021-04-28 14:35:07Z

2

Assuming you expect your double quotes to always be balanced, you may just use String#replaceAll here for a more terse solution:

String input = "Here is \"some text\": and also \"some other text\":";
String output = input.replaceAll("\"(.*?)\":", "<strong>$1:</strong>");
System.out.println(output);

This prints:

Here is <strong>some text:</strong> and also <strong>some other text:</strong>

answered Apr 28, 2021 at 14:35

Tim Biegeleisen

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