how to split a string with special pattern using regular expression and save it to a list in python

Question

I have a string like this:

'{"po": 118.0, "count": 1.0}, {"po": 124.0, "count": 1.0}, {"po": 132.0, "count": 2.0}'

I want to split this string and save them into a list like this using python:

 ['{"po": 118.0, "count": 1.0}', '{"po": 124.0, "count": 1.0}', '{"po": 132.0, "count": 2.0}']

When I do this :

r=re.split(r"['{}']", s)

But I receive this result, which is not what I want :

['', '"po": 118.0, "count": 1.0', ', ', '"po": 124.0, "count": 1.0', ', ', '"po": 132.0, "count": 2.0', '']

Would you please guide me on how to use a regular expression to split the string?

Any help is really appreciated.

Tim Biegeleisen · Accepted Answer · 2021-04-29 05:57:12Z

1

This looks a lot like a fragment from some JSON content, and, if so, then you might want to work with the original valid JSON. If you must proceed at your current starting point, then I would suggest using re.findall here:

inp = '{"po": 118.0, "count": 1.0}, {"po": 124.0, "count": 1.0}, {"po": 132.0, "count": 2.0}'
output = re.findall(r'\{.*?\}', inp)
print(output)

This prints:

['{"po": 118.0, "count": 1.0}', '{"po": 124.0, "count": 1.0}', '{"po": 132.0, "count": 2.0}']

This approach should be fine assuming your input doesn't have any nested content.

answered Apr 29, 2021 at 5:57

Tim Biegeleisen

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tshiono · Accepted Answer · 2021-04-29 06:02:08Z

1

Would you please try the following:

import re

str = '{"po": 118.0, "count": 1.0}, {"po": 124.0, "count": 1.0}, {"po": 132.0, "count": 2.0}'
r = re.split(r'(?<=}),\s*(?={)', str)
print(r)

Output:

['{"po": 118.0, "count": 1.0}', '{"po": 124.0, "count": 1.0}', '{"po": 132.0, "count": 2.0}']

answered Apr 29, 2021 at 6:02

tshiono

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