I have a function defined in my .zshenv like this:
function my_func() {
echo $1
}
I then execute a bash script from the zsh which its content is:
type my_func
I got an error: /tmp/test.bash: line 3: type: my_func: not found
While if I type type my_func from the zsh I got: my_func is a shell function from
Is there a way to use zsh defined function in a bash script? It seems to work for the exported variables
Bash itself can export its functions to other bash shells. It does so by exporting a string environmental variable of the form:
BASH_FUNC_functionNameHere%%=() { functionBodyHere; }
So in theory you could use the following zsh-command to export your function for bash:
export "BASH_FUNC_my_func%%=() { $(echo; typeset -f my_func | tail -n+2) }"
However, this does not work because zsh doesn't allow %% in identifiers.
Depending on how you start bash, you might be able to inject the function definition into the bash process.
When running a bash script like bash myScript or ./myScript you can use bash -c "$(typeset -f my_func); export -f my_func; myScript" instead.
When starting an interactive bash shell using bash, you can use bash -c "$(typeset -f my_func); export -f my_func; exec bash" instead.
Either way, your function has to be a polyglot. That is, the source code of the function has to be understood by both zsh and bash. Above approach is not really viable if you want to export many functions or want to call many bash scripts.
It would be easier to define each of your functions inside its own script file and add the locations of those scripts to $PATH. That way you can call your "functions" from every shell and they will always work independently from your current shell.
Replacing the functions by script files only works if your functions don't want to modify the parent shell. cd or setting variables has no effect on the caller. If you want to do stuff like this, you can still use a script file, but then have to source it using . myFunctionFile. For sourcing, the source code has to be a polyglot again.
bash_func=$(printenv BASH_FUNC_my_func%%).
export "BASH_FUNC_... does not work in zsh, but that doesn't mean that it works in bash (as expected, it doesn't; neither in bash 4, nor bash 5). The other commands worked in bash 4.4.12 and 5.1.4. For the script version (first bullet point) I just added a missing export. ¶ BTW Your suggestion assumes that OP wanted to export a function from bash to zsh when they actually want to export it the other way around.
my_func 'a b c'(observe the difference in spacing in the output!).