Count the number of arguments actually passed to a python function

Question

I would like to retrieve the number of arguments that have been passed to a Python function. In fact I am writting a Matlab code in Python and in Matlab, the code line is :

if (nargin > 2)
    ...
end

I would like to do the same thing in Python with a function that have this form : def my_func(a,b,c=3,d=4, ...):

When calling it, I would be able to retrieve the number of passed arguments, for instance :

my_func(1,2) would return 2

my_func(1,2,3) would return 3

my_func(1,2,3,4) would return 4 etc.

I have seen some topics but only giving the number of arguments and description of the function, and not the number of arguments passed when calling it in a script.

I hope that I am clear in explaining my issue.

Best regards, MOCHON Rémi

I don't think that is possible. Although this approach might work for some cases - put a check explicitly in your code that how many values received are exactly equal to the default values specified :) — edusanketdk
– edusanketdk, Commented May 3, 2021 at 13:12

Gurudev Kumar · Accepted Answer · 2022-04-12 05:34:34Z

2

Below code will work for you

def param_count(*args):
    return len(args)

answered Apr 12, 2022 at 5:34

Gurudev Kumar

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Marios Mitalidis · Accepted Answer · 2021-05-03 13:19:45Z

0

Not exactly what you ask for, but a simple way to achieve this is to count the number of args and kwargs using a decorator, and then pass it to the function.

The decorator will look like this:

def count_nargin(func):
    def inner(*args, **kwargs):
        nargin = len(args) + len(kwargs)
        return func(*args, **kwargs, nargin=nargin)
    return inner

You will then have to modify your function to accept the nargin parameter:

@count_nargin
def my_func(a,b,c=3,d=4,nargin=None):
    print(nargin)

For example, calling the above function returns:

>>> my_func(1,2)
2

>>> my_func(1,2,3)
3

answered May 3, 2021 at 13:19

Marios Mitalidis

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