how to compare if two values are the same but different cases in python

Question

So the exercise I'm doing goes:

086 Ask the user to enter a new password. Ask them to enter it again. If the two passwords match, display “Thank you”. If the letters are correct but in the wrong case, display th emessage “They must be in the same case”,otherwise display the message “Incorrect”.

My attempt looks like this:

passw = input("Enter password: ")
passw2 = input("Enter password again: ")
if passw == passw2:
    print("Thank you.")
elif passw != passw2 and passw.lower == passw2.lower:
    print("They must be in the same case.")
else: 
    print("Incorrect.")

That didn't give me the result I was hoping for though. This should be really simple but as you can tell I'm a beginner :) Thank you in Advance!

Marcel

One minor change, if passw == passw2 fails in first if case, do we still need to check passw != passw2 in other elif case. — Chirag Patel
– Chirag Patel, Commented May 8, 2021 at 10:07

azro · Accepted Answer · 2021-05-08 10:05:39Z

3

That passw.lower is a method, the method itself, you may call it to have the password in lowercase. Also remove passw != passw2 in second ìf that's mandatory True

if passw == passw2:
    print("Thank you.")
elif passw.lower() == passw2.lower():
    print("They must be in the same case.")
else:
    print("Incorrect.")

More

passw = "Abc"

print(passw.lower(), "/", type(passw.lower()))
# abc / <class 'str'>

print(passw.lower, "/", type(passw.lower))
# <built-in method lower of str object at 0x00000202611D4730> / <class 'builtin_function_or_method'>

answered May 8, 2021 at 10:05

azro

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Comments

TheEagle · Accepted Answer · 2021-05-08 10:11:01Z

The problem is that your elif condition always evaluates to True:

elif passw != passw2 and passw.lower == passw2.lower:

str.lower is a function, and comparing a function with the same function logically ends up being True. You have to call the functions instead and compare their results. Additionally, you are doing comparing passw and passw twice : once you check if they are the same in the if condition, and once you check if they are not the same in the elif condition. This is useless, because the elif condition will only ever be executed when the if condition was False. Following the working code:

passw = input("Enter password: ")
passw2 = input("Enter password again: ")
if passw == passw2:
    print("Thank you.")
elif passw.lower() == passw2.lower():
    print("They must be in the same case.")
else: 
    print("Incorrect.")

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