Printing nested list in this specific format

Question

I am going through automate the boring stuff, diong chapter 6 first practice problems:

tableData = [['apples', 'oranges', 'cherries', 'banana'],
         ['Alice', 'Bob', 'Carol', 'David'],
         ['dogs', 'cats', 'moose', 'goose']]

I would like to tried the following output without using zip function or map cause I am forcing myself to get deeper understanding regarding list manipulation without using those methods.

apples | Alice | dogs

oranges| Bob | cats

cherries | Carol | moose

banana | David | goose

So far I have tried the following:

for i in range(len(tableData[0])):
    print(' '.join(subLst[i] for subLst in tableData))

which does give me intended output, but the range parameter I used feels kinda brutish, so is there any other way I could solve this problem ??

If the problem assumes that all sublists have the same length, then I don't see anything wrong with your approach. — Anis R.
– Anis R., Commented May 27, 2021 at 22:16
Yeah based on the description to that problem we can assume that all sublist will have same length.Again it just to sate my inner curiosity if there is better way to the solve it. — Hat Straw
– Hat Straw, Commented May 27, 2021 at 22:31
Despite your focus, print(*map(' '.join, zip(*tableData)), sep='\n') is almost irresistible, again assuming common length of sublists. I do want to know why David missed out on plurals though. — Joffan
– Joffan, Commented May 27, 2021 at 22:41

sahasrara62 · Accepted Answer · 2021-05-27 22:41:43Z

you can store the each value according to the index in a hash table (dictionary) and then print the result or corresponding index values together

tableData = [['apples', 'oranges', 'cherries', 'banana'],
         ['Alice', 'Bob', 'Carol', 'David'],
         ['dogs', 'cats', 'moose', 'goose']]
         
dic = {}
for sublist in tableData:
    for i, v in enumerate(sublist):
        if i not in dic:
            dic[i]=[v]
        else:
            dic[i].append(v)
            

for k, v in dic.items():
    print(" | ".join(v))

output

apples | Alice | dogs
oranges | Bob | cats
cherries | Carol | moose
banana | David | goose

NOTE: This consider the lenght of sublist is same, if length is different then index value for that index will be shown but not able to know the value belong to which sublist index, to solve that first one need to make all sublist of same length and then proced with this code.

Andreas · Accepted Answer · 2021-05-27 23:34:12Z

0

You could use list comprehension:

[[row[i] for row in tableData] for i in range(len(tableData[0]))]

[['apples', 'Alice', 'dogs'],
 ['oranges', 'Bob', 'cats'],
 ['cherries', 'Carol', 'moose'],
 ['banana', 'David', 'goose']]

answered May 27, 2021 at 23:34

Andreas

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