passing value between functions

Question

I'm having some difficulty passing values and arrays between this two functions

Here's the code:

 $(document).ready(function(){
        ....
        ....    
    var srcImageFS =$('#imageAnimated').attr('src');    
    var array = []; 
    $('.myLightbox').each(function(i) {
         array.push($('.myLightbox').eq(i).attr('href'));
    });

    $('#rightArrowFS').click(function(array, srcImageFS ){
            alert(array +' || --> ' +srcImageFS );
            imageRight();

        });
...
...
});

and

function imageRight(array, srcImageFS ){
        $('#imageAnimated').fadeOut();
        $('#imageAnimated').src(array[i+1]);
        $('#imageAnimated').fadeIn();
        srcImageFS = $('#imageAnimated').src();
        arrowsState(array, srcImageFS );
}

what are you trying to pass? Is imagemAnimada same as imageAnimated ? i think you have a typo here — raym0nd
– raym0nd, Commented Jul 21, 2011 at 16:06
Just uppdate the code wit the correct names. Sorry about that. I'm trying to pass array and srcImageFS. I trid to imageRight( array, srcImageFS); but without success. The alert gives me [object Object] || --> undefined — saomi
– saomi, Commented Jul 21, 2011 at 16:12

dtanders · Accepted Answer · 2011-07-21 16:36:55Z

1

In the example code, you don't actually try to pass anything to imageRight - the parameter list is empty. Also, you overwrite the value of srcImageFS inside imageRight before using it.

srcImageFS is undefined because jQuery couldn't find a src attribute on $('#imageAnimated') so your selector might be wrong, too.

imageRight(array, srcImageFS);

Will actually call the function with the arguments you want.

answered Jul 21, 2011 at 16:36

dtanders

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2 Comments

saomi Over a year ago

yap you are right. thanks. on the second block of code I want to change the source of #imageAnimated. I tried $('#imageAnimated').src(array[i+1]); , but var i is not passed. Do you have any idea how can I do it??

dtanders Over a year ago

.attr('src', array[i+1]) src is an attribute api.jquery.com/category/attributes

Parv Sharma · Accepted Answer · 2011-07-21 16:36:12Z

1

in the document.ready function where ur calling the imageRight() function u should instead call imageRight(array, srcImageFS ) ur nt passing any values to the function

answered Jul 21, 2011 at 16:36

Parv Sharma

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