How to get a specific length of string in my array?

Question

I am generating an integer from 5-10.

once I generate an integer ranging from 5-10, the loop should choose a string on my array that has a character length based on the random integer that is generated.

example:

random integer generated: 10

the system should display a string that has a length of 10 character so either it will display the testNames1 or testNames2 because it has 10 character length

I tried doing this on my code, but it doesn't work.

<?php
  function getName(){

    $names = array(
        'Juans',
        'Luisss',
        'Pedroaa',
        'testNames1',
        'testNames2',
        'testName3',
        'test', //This should not be return because im only generating a number random of 5-10 and this character has only 4 character length
        'tse', //This should not be return because im only generating a number random of 5-10 and this character has only 3 character length
        // and so on
    );
    
    $randomString = "";
    
    for ($i = 0; $i <count($names); $i++) {
        $value = rand(5,10);
        $length_string = strlen($names[$i]);

        if ($value == $length_string) {
            return "name:".$names[$i].$value;
        }
 
    }

  }

echo getName();
?>

Can anyone help me on how to do this?

Nigel Ren · Accepted Answer · 2021-06-07 06:34:20Z

1

What you need to do is first create a list of strings matching the length and then pick a random one from them. So loop through all of the strings, check the length and add to $match, then use array_rand() to pick one of the matching ones...

function getName($random_num)
{
    $names = array
    (
        'Juans',
        'Luisss',
        'Pedroaa',
        'testNames1',
        'testNames2',
        'testName3',
        'test', //This should not be return because im only generating a number random of 5-10 and this character has only 4 character length
        'tse', //This should not be return because im only generating a number random of 5-10 and this character has only 3 character length
        // and so on
    );
    $randomString = "";
    $match = [];
    foreach ( $names as $name )
    {
        $length_string = strlen($name);
        if ($random_num == $length_string)
        {
            $match[] = $name;
        }
    }
    // If non found return ''
    return !empty($match) ? $match[array_rand($match)] : '';
}

answered Jun 7, 2021 at 6:34

Nigel Ren

57.3k11 gold badges49 silver badges59 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

shadow_blade Over a year ago

Thank you. this helps me a lot Sir! I already understand my mistake, this solves too the choosing of one value in multiple value that has same length of character! thank you sir!

John Doe · Accepted Answer · 2021-06-07 06:19:22Z

1

You can try the below code. You was adding the below line in the loop that was wrong.

$value = rand(5,10);

Now, This program will return the name that will be equal to the generated random number that is between 5 to 10. Also it will return the message if no name exist according to the random number. For example: 8

<?php
function getName($random_num)
{
    $names = array
    (
        'Juans',
        'Luisss',
        'Pedroaa',
        'testNames1',
        'testNames2',
        'testName3',
        'test', //This should not be return because im only generating a number random of 5-10 and this character has only 4 character length
        'tse', //This should not be return because im only generating a number random of 5-10 and this character has only 3 character length
        // and so on
    );
    $randomString = "";
    for ($i = 0; $i <count($names); $i++)
    {
        $length_string = strlen($names[$i]);
        if ($random_num == $length_string)
        {
            return "name:".$names[$i].$random_num;
        }
    }
}
$random_num = rand(5,10);
$returned_name = getName($random_num);
if ($returned_name == "")
{
    echo "No Name Exist having length: " . $random_num;
}
else
{
    echo $returned_name;
}
?>

answered Jun 7, 2021 at 6:19

John Doe

1,4341 gold badge7 silver badges14 bronze badges

5 Comments

shadow_blade Over a year ago

OH! I WAS SO CLOSE ON MY PROBLEM! :(. THANK YOU VERY MUCH SIR! I APPREICATE IT SO MUCH

shadow_blade Over a year ago

sir can i still ask, what if there is 2 string that has a same lenght of character? how can i randomly choose 1 from them?

John Doe Over a year ago

This program will return only the first one from the array. It will not return 2 values.

shadow_blade Over a year ago

is there a way sir to randomly choose one from the 2 values that has same length?

John Doe Over a year ago

Yes, in that case you have to return the array from the function. and after that use the array_rand function to select one key from the array randomly

vins · Accepted Answer · 2021-06-07 08:10:12Z

you are almost there ... you just need to generate random number outside then make checks like this :

<?php
function getName($random_num)
{
    $matches= [];
    $names = array(
        'Juans',
        'Luisss',
        'Pedroaa',
        'testNames1',
        'testNames2',
        'testName3',
        'test', //This should not be return because im only generating a number random of 5-10 and this character has only 4 character length
        'tse', //This should not be return because im only generating a number random of 5-10 and this character has only 3 character length
        // and so on
    );

    $value = rand(5,10);
  
    for ($i = 0; $i <count($names); $i++) {
       
        if(strlen($names[$i]) == $value)
        {
            $matches[] = $names[$i];
          
        }
    }
 
    print_r($matches);
}

?>

Collectives™ on Stack Overflow

How to get a specific length of string in my array?

3 Answers 3

1 Comment

5 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

1 Comment

5 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related